176
3 Superposition et le théorème de l’extra-élément
r
L
10Ω
:=
R
2
10kΩ
:=
R
3
120Ω
:=
R
4
1.2kΩ
:=
R
5
3.3kΩ
:=
L
1
1H
:=
|| x y
,
( )
x y
⋅
x y
+
:=
Z
inf
R
2
R
4 || R
3
R
5
+
(
)
+
10.8883⋅kΩ
=
:=
R
d
r
L
R
2
+
R
5
R
4
+
(
) || R
3
+
10.1269⋅kΩ
=
:=
R
n
R
2 || R
4
(
) R
3
+
|| R
5
r
L
+
885.3817Ω
=
:=
R
0a
r
L || R
2
R
5 || R
4
+
(
)
1
R
2
R
4
+
(
) || r
L
R
5
+
(
)
r
L || R
2
R
5 || R
4
+
(
)
R
3
r
L
R
2
+
(
) || R
4
R
5
+
(
)
⋅
+
1
R
3
r
L
R
2
+
(
) || R
4
R
5
+
(
)
+
⋅
951.9525Ω
=
:=
R
0b
R
2
R
4
+
(
) || r
L
R
5
+
(
)
1
r
L || R
5
R
2 || R
4
+
R
3
+
1
R
2
r
L
+
(
) || R
4
R
5
+
(
)
R
3
+
⋅
951.9525Ω
=
:=
Z
3 s
( ) R
0a
1
s L
1
⋅
R
n
+
1
s L
1
⋅
R
d
+
⋅
:=
Z
1 s
( ) Z
inf
1
R
n
s L
1
⋅
+
1
R
d
s L
1
⋅
+
⋅
:=
1
10
100
1 10
3
×
1 10
4
×
1 10
5
×
60
70
80
20 log
Z
1 i 2
⋅ π f
k
⋅
(
)
Ω
10
,
⋅
20 log
Z
3 i 2
⋅ π f
k
⋅
(
)
Ω
10
,
⋅
f
k
1
10
100
1 10
3
×
1 10
4
×
1 10
5
×
0
20
40
60
arg Z
1 i 2
⋅ π f
k
⋅
(
)
(
)
180
π
⋅
arg Z
3 i 2
⋅ π f
k
⋅
(
)
(
)
180
π
⋅
f
k
Figure 3.49 Utiliser l’EET ou la fonction de transfert généralisée mène à des résultats rigoureusement identiques.