159
3.2 Le théorème de l’extra-élément
100
:=
R
C
10kΩ
:=
r
π
1.2kΩ
:=
R
E
470Ω
:=
R
f
150kΩ
:=
C
1
0.1μF
:=
1
1 0
100
30
20
10
0
10
20
30
f
k
1
1 0
100
1×10
1×10
1×10
3
4
5
1×10
1×10
1×10
3
4
5
–180
–160
–140
–120
–100
f
k
H
1 s
( )
β R
C
⋅
r
π
β 1
+
(
)R
E
⋅
+
−
1
r
π
β
R
E 1
1
β
+
⋅
+
R
f
−
1
R
C
R
f
+
⋅
1
1
1
C
1 s
⋅
R
C
R
f
+
(
) R
E
r
π
+
R
E
β
β
⋅
+
(
)
⋅
R
C
R
E
+
R
f
+
r
π
+
R
C
β
⋅
+
R
E
β
⋅
+
⋅
+
⋅
:=
20 log H
1 i 2
⋅ π 1
⋅ Hz
(
) 10
,
(
)
⋅
22.189
−
=
20 log H
1 i 2
⋅ π 10
6
⋅ Hz
(
) 10
,
⋅
25.666
=
ω p
1
C
1
R
C
R
f
+
(
) R
E
r
π
+
R
E
β
⋅
+
(
)
⋅
R
C
R
E
+
R
f
+
r
π
+
β R
C
R
E
+
(
)
⋅
+
⋅
:=
f
p
ω p
2π
247.028Hz
=
:=
R
C
R
f
+
(
) R
E
r
π
+
R
E
β
⋅
+
(
)
⋅
R
C
R
E
+
R
f
+
r
π
+
R
C
β
⋅
+
R
E
β
⋅ +
6.443k
Ω
=
H
inf
β R
C
⋅
r
π
β 1
+
(
)R
E
⋅
+
1
r
π
β
R
E 1
1
β
+
⋅
+
R
f
−
1
R
C
R
f
+
⋅
:=
H
3 s
( )
H
inf
−
1
1
ω p
s
+
⋅
:=
20 log H
1 i 2
⋅ π f
k
⋅
(
) 10
,
(
)
⋅
20 log H
3 i 2
⋅ π f
k
⋅
(
) 10
,
(
)
⋅
arg H
1 i 2
⋅ π f
k
⋅
(
)
(
)
180
π
⋅
arg H
3 i 2
⋅ π f
k
⋅
(
)
(
)
180
π
⋅
Figure 3.35 Les résultats de Mathcad
®
confirment ce que nous avons simulé. Les points principaux
sont exactement ceux retournés par la simulation SPICE.
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