586
10 Particle Physics – II
10.87 (a) P e (t) = 1 − P μ (t) = sin
2 2θ sin
2
(E2−E1)
2
t
(b) P μ (t) = P e (t)
1 − sin
2 2θ sin
2
(E 2 − E 1 )
2
t
= sin
2 2θ sin
2
(E 2 − E 1 )
2
t
2 sin
2 2θ sin
2
(E 2 − E 1 )
2
t
= 1
Restoring to practical units the above equation becomes
2 sin
2 2θ sin
2
Δm
2 c
4
2E
t
= 1
where Δm
2
= m 2
2
− m 1
2 and θ = 34
0
If m 1 and m 2 are in eV/c
2 , and E in MeV and L the distance from the source,
then the last equation becomes
2 sin
2 2θ sin
2
1.27Δm
2
.L
E
= 1
Inserting θ = 34
0
, Δm
2
= 5
2
− 3
2
= 16 and E = 1,000 MeV, we find
L = 426 m, giving t = L/C = 1.42 × 10
−6 s.
10.88 τ (μ
+
→ e
+
ν e ν τ ) =
G
2
(c)
6
m
5
μ
192π 3
(1)
G
2
∼ g
2
M
2
w , where M w is the mass of W-boson.
From the τ lepton lifetime and formula (1) for the dependence of parent
particle mass, we can test the universality of the couplings g μ and g τ to the
W – boson
g τ
g μ
4
= B
τ
+
→ e
+
ν e ν τ
m μ
m τ
5 τ μ
τ τ
Inserting B = 0.178, m μ = 105.658 MeV/c
2
, m τ = 1777.0 MeV/c
2 , τ μ =
2.197 × 10
−6 s and τ τ = 2.91 × 10
−13 s, we find
g τ
g μ
= 0.987
Comment: From the branching fractions for τ
+
→ e
+
ν e ν τ and τ
+
→
μ
+
ν μ ν τ the ratio g μ /g e = 1.001. A similar result is obtained from the
branching ratio of π → eν and π → μe, proving thereby different flavours
of leptons have identical couplings to the W
± bosons.
The principle of universality is equally valid for the Z
0 coupling. Thus,
the branching fractions are predicted as
Z
0
→ e
+ e
− : μ
+
μ
− : τ
+
τ
−
= 1 : 1 : 1
in agreement with the experimental ratios. Formula (1) affords the most accurate determination of G, the Fermi constant because the mass and lifetime of
muon are precisely known by experiment.
10 Particle Physics – II
10.87 (a) P e (t) = 1 − P μ (t) = sin
2 2θ sin
2
(E2−E1)
2
t
(b) P μ (t) = P e (t)
1 − sin
2 2θ sin
2
(E 2 − E 1 )
2
t
= sin
2 2θ sin
2
(E 2 − E 1 )
2
t
2 sin
2 2θ sin
2
(E 2 − E 1 )
2
t
= 1
Restoring to practical units the above equation becomes
2 sin
2 2θ sin
2
Δm
2 c
4
2E
t
= 1
where Δm
2
= m 2
2
− m 1
2 and θ = 34
0
If m 1 and m 2 are in eV/c
2 , and E in MeV and L the distance from the source,
then the last equation becomes
2 sin
2 2θ sin
2
1.27Δm
2
.L
E
= 1
Inserting θ = 34
0
, Δm
2
= 5
2
− 3
2
= 16 and E = 1,000 MeV, we find
L = 426 m, giving t = L/C = 1.42 × 10
−6 s.
10.88 τ (μ
+
→ e
+
ν e ν τ ) =
G
2
(c)
6
m
5
μ
192π 3
(1)
G
2
∼ g
2
M
2
w , where M w is the mass of W-boson.
From the τ lepton lifetime and formula (1) for the dependence of parent
particle mass, we can test the universality of the couplings g μ and g τ to the
W – boson
g τ
g μ
4
= B
τ
+
→ e
+
ν e ν τ
m μ
m τ
5 τ μ
τ τ
Inserting B = 0.178, m μ = 105.658 MeV/c
2
, m τ = 1777.0 MeV/c
2 , τ μ =
2.197 × 10
−6 s and τ τ = 2.91 × 10
−13 s, we find
g τ
g μ
= 0.987
Comment: From the branching fractions for τ
+
→ e
+
ν e ν τ and τ
+
→
μ
+
ν μ ν τ the ratio g μ /g e = 1.001. A similar result is obtained from the
branching ratio of π → eν and π → μe, proving thereby different flavours
of leptons have identical couplings to the W
± bosons.
The principle of universality is equally valid for the Z
0 coupling. Thus,
the branching fractions are predicted as
Z
0
→ e
+ e
− : μ
+
μ
− : τ
+
τ
−
= 1 : 1 : 1
in agreement with the experimental ratios. Formula (1) affords the most accurate determination of G, the Fermi constant because the mass and lifetime of
muon are precisely known by experiment.
