Exercices de chimie des solides
113
Il vient alors :
T(K) K S = exp –[ ]
n/N
n (mole
−1 ) n VO (cm
−3 ) n VZr (cm
−3 )
1 000 exp(−31,304) 2,93.10
−5
1,76.10
19
7,84.10
17
3,94.10
17
1 200
exp(−26,08) 1,67.10
−4
1.10
20
4,50.10
18
2,25.10
18
1 400
exp(−22,36) 5,79.10
−4
3,48.10
20
1,55.10
19
7,78.10
18