Design of Automatic Multipurpose Indian Flatbread Maker
505
Vertical force (F V ) on bearing,
• Bearing inner diameter = 15 mm
• Power transmitted from motor = 0.5 Hp = 370 w
• Angular speed of sprocket B = 11.52 RPM = 1.2 rad/s
Total torque (τ) transmitted is given by,
τ =
Power
Angular speed
=
370 w
1.2 rad./s
= 294.438 Nm
(10)
F V =
Torque(τ )
Perpendicular distance
=
294.438 Nm
0.125 m
= 2.355 kN
(11)
Horizontal force (F H ) on bearing,
• Angular speed of sprocket D = 8 RPM = 0.75398 rad/s
τ =
Power
Angular speed
=
370 w
0.75398 red/s
= 490.729 Nm
(12)
F H =
Torque(τ )
Perpendicular distance
=
490.729 Nm
0.2 m
= 2.453 kN
(13)
So, total bearing load,
F R =
F
2
V + F
2
H = 3.404 kN
(14)
For UCT204 type bearing (used for mounting the shaft holding sprocket D)
• Horizontal force (F H ) = 2.453 kN
• Vertical force (F V ) = 0 N
• Total bearing load = 2.453 kN.
3.3 Stress Calculations for Shaft
For shaft mounted on UCT 204 type bearing,
• Diameter = 12 mm
• Horizontal force acting on the shaft = 2.453 kN
• Bending moment (M) = 0.460 m × 2.453 kN = 1128.38 Nm.
• Maximum distance from center (y) = 6 mm
• Moment of inertia for a shaft (rod) is given by Bhandari [5],