147
3.2 Le théorème de l’extra-élément
R
1
250Ω
:=
R
2
:=
R
3
18kΩ
12kΩ
: =
R
4
150Ω
:=
R
5
470Ω
:=
L
:=10mH
|| x y
,
( )
x y
⋅
x y
+
:=
H
2 s
( )
R
4
R
4
R
2
+
1
R
1 R
2
+
1
R
1
R
3
+
s L
⋅
+
1
R
1 || R
3
R
2 || R
4
+
s L
⋅
+
⋅
:=
H
3 s
( )
R
3 || R
4
R
1 || R
2
R
3 || R
4
+
1 s
L
R
1 R
2
+
1
R
1
R
3
+
+
1 s
L
R
1 || R
3
R
2 || R
4
+
⋅
+
⋅
:=
H
0
R
3 || R
4
R
1 || R
2
R
3 || R
4
+
ω
=
:
z
R
1
R
2
+
1
R
1
R
3
+
L
⋅
:=
ω p
R
1 || R
3
R
2 || R
4
+
(
)
L
:=
H
4 s
( ) H
0
1
s
ω z
+
1
s
ω p
+
⋅
:=
f
z
ω z
2π
192.294kHz
=
:=
f
p
ω p
2π
6.282kHz
=
:=
50
−
40
−
30
−
20
−
10
−
0
20 log H
2 i 2
⋅ π f
k
⋅
(
) 10
,
(
)
⋅
20 log H
3 i 2
⋅ π f
k
⋅
(
) 10
,
(
)
⋅
20 log H
4 i 2
⋅ π f
k
⋅
(
) 10
,
(
)
⋅
f
k
100
1×10
3
1×10
4
1×10
5
1×10
6
1×10
7
80
−
60
−
40
−
20
−
0
arg H
2 i 2
⋅ π f
k
⋅
(
)
(
)
180
π
⋅
arg H
3 i 2
⋅ π f
k
⋅
(
)
(
)
180
π
⋅
arg H
4 i 2
⋅ π f
k
⋅
(
)
(
)
180
π
⋅
f
k
100
1×10
3
1×10
4
1×10
5
1×10
6
1×10
7
Figure 3.25 Mathcad
®
confirme que les équations (3.66) et (3.69) sont identiques.
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