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CHAPTER 34
Thus,
This is the normal component, and we already found the tangential component as
Note that we avoided a direct computation of v Ip, which is usually tedious.
34.108 Find the tangential and normal components of the acceleration vector for the curve R = (f
2 ,/
3 )R' = (2f, 3f
2 ), R" = (2,6r) = 2(1,30- Then
Hence,
By the Pythagorean theorem, |R'f = \dvldt\
2 + (v
2 /p)
2 . Hence,
So,
tangential component as
is the normal component of the acceleration vector, and we already found the