Part II: The Answers
362
Answers
501–600
561.
1
Using elementary antiderivative formulas gives you
sec tan
sec
sec
sec
cos
cos
x
xdx
x
0
3
0
3
3
0
1
3
1
0
2 1
1
π
π
π
π
∫
=
=
−
=
−
= −
=
562.
12
4
ln
Using the basic antiderivative formula for an exponential function gives you
4
4
4
4
4
4
4
12
4
1
2
1
2
2
1
x
x
dx
∫
=
=
−
=
ln
ln
ln
ln
563.
π
2
2
2
−
Using elementary antiderivative formulas gives you
x
x dx
x
x
−
(
) =
+






=
+





 − +
(
)
=
∫
sin
c os
cos
c os
0
2
0
2
2
2
2
0
0
2
π
π
π
π
π − −





 − +
(
)
=
−
1
0 1
2
2
2
π
564.
285
4
Using elementary antiderivative formulas gives you
x x dx
x
x
+
(
) = +






=
+
−
+






=
∫
3
1
4
2
4
1
4
2
4
2
4
2
4
4
2
4
4
1
2
1
4
285
4