Part II: The Answers
208
233.
π
2
As the x values approach ∞, the y values approach π
2
so that lim
x
f x
→∞
( ) = π
2
.
234.
2
As the x values approach –∞, the y values approach 2 so that lim
x
f x
→−∞
( ) = 2.
235.
2
As the x values approach ∞, the y values approach 2 so that lim x f x
→∞
( ) = 2.
236.
0
Divide the numerator and denominator by the highest power of x that appears in the
denominator, x
1
, and simplify:
lim
lim
lim
x
x
x
x
x
x
x
x
x
x
→∞
→∞
→∞
+
=
+
=
+
1
3
4
1
3
4
1
3 4
Then apply the limit:
= +
=
0
3 0
0
Answers
201–300
208
233.
π
2
As the x values approach ∞, the y values approach π
2
so that lim
x
f x
→∞
( ) = π
2
.
234.
2
As the x values approach –∞, the y values approach 2 so that lim
x
f x
→−∞
( ) = 2.
235.
2
As the x values approach ∞, the y values approach 2 so that lim x f x
→∞
( ) = 2.
236.
0
Divide the numerator and denominator by the highest power of x that appears in the
denominator, x
1
, and simplify:
lim
lim
lim
x
x
x
x
x
x
x
x
x
x
→∞
→∞
→∞
+
=
+
=
+
1
3
4
1
3
4
1
3 4
Then apply the limit:
= +
=
0
3 0
0
Answers
201–300