5.9 Numerical Examples
153
Fig. 5.11 Simply supported beam
Boundary conditions are
(i) σ y = 0 for y = ±h
(ii) τ xy = 0 for y = ±h
(iii) −
+h
−h
τ xy dy =
W
2
for x = ±L
(iv)
+h
−h
σ x dy = 0 for x = ±L
(v)
+h
−h
σ x y dy = 0 for x = ±L
Now,
Condition (i)
This condition is satisfied since σ y = 0.
Condition (ii)
0 = −
ba
2
2
+ c
∴ c =
bh
2
2
153
Fig. 5.11 Simply supported beam
Boundary conditions are
(i) σ y = 0 for y = ±h
(ii) τ xy = 0 for y = ±h
(iii) −
+h
−h
τ xy dy =
W
2
for x = ±L
(iv)
+h
−h
σ x dy = 0 for x = ±L
(v)
+h
−h
σ x y dy = 0 for x = ±L
Now,
Condition (i)
This condition is satisfied since σ y = 0.
Condition (ii)
0 = −
ba
2
2
+ c
∴ c =
bh
2
2