Solutions to exercises
169
7. Based on the preceding relation, we have
RT
4F
J
h
2
O 2
,
σ =
8.314 1725
4 96 480 0.4
8.8 10
h
2
10
#
σ =
−
#
#
#
#
9.1 10 S cm
h
4
1
#
σ =
−
−