2 Beam Dynamics
17
Fig. 2.2 Vector diagram showing differential changes in momentum for a particle trajectory
We will now briefly derive an expression for the magnetic rigidity of a relativistic.
A particle has a relativistic momentum vector p and travels perpendicular to a field
B which is into the plane of the diagram (Fig. 2.2).
We write the Lorentz force on the particle on its circular path as
F Lorent z = e ∗ (v × B)
Assuming an idealized homogeneous dipole magnet along the particle orbit,
having pure vertical field lines, the condition for a perfect circular orbit is defined
as equality between this Lorentz force and the centrifugal force.
F cent rif ugal =
γ mv 2
ρ
This yields the following condition for the idealized ring:
Bρ =
p
e
where we are referring to protons and have accordingly set q = e. We conclude
that the beam rigidity Bρ, given by the magnetic field and the size of the machine,
defines the momentum of a particle that can be carried in the storage ring, or in
other words, it ultimately defines, for a given particle energy, the magnetic field of
the dipole magnets and the size of the storage ring.
We really should use the units Newton-second for p and express e in Coulombs
to give (Bρ) in Tesla·metres. However, in charged particle dynamics we often talk
in a careless way about the ‘momentum’ pc. This actually has the dimensions of an
energy and is expressed in units of GeV.
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