Direct Current and Transient Analysis
155
MATLAB Solution
>> R = [-1 1 1;10 5 0;0 -5 30];
>> V = [0;10;0];
>> I = inv(R)*V; % Solves for the loop currents
>> Result = [I(1) I(2) I(3)];
>> % Results are printed
>> disp(‘*********************************’);
>> disp(‘**********R E S U L T S*********’);
>> disp(‘*********************************’);
>> disp(‘
The currents I1, I2, I3 are:’);
>> disp(Result)
>> disp(‘
amp.
amp.
Amp.’);
>> disp(‘*********************************’);
************************************
**********R E S U L T S************
************************************
The currents I1, I2, I3 are:
0.7000
0.6000
0.1000
amp.
amp.
amp.
***********************************
Example 2.14
Solve for the loop currents I 1 and I 2 shown in the circuit diagram of Figure 2.53
(Example 2.13) by using
i. The matrix operation I = R\V
ii. The symbolic method
iii. Compare the results of i and ii with the solution obtained in Example 2.13
ANALYTICAL Solution
The loop equations are
For loop# I, 15 * I 1 − 5 * I 2 = 10
For loop# II, −5 * I 1 + (5 + 10 + 20) * I 2 = 0
FIGURE 2.52
Network of Example 2.13.
5 Ω
10 V
10 Ω
−
+
I 2
10 Ω
20 Ω
I 1
Loop # 1
Loop # 2
I 3
CRC_47760_CH002.indd 155
CRC_47760_CH002.indd 155
7/23/2008 1:38:49 PM
7/23/2008 1:38:49 PM