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Table 2.7 Cv for q average values
Chapter 2
Q and T steel
Normal steel
Ave. aluminum
Cv
4- 8.33%
4- 5.26%
4- 7.33%
In the equation
Kf = 1 + q(K, - 1)
For qhigh
qhigh = ?/(1 -k 3Cvq) = 1.2499 ?/---- ?/[+3(0.0833)]
Kthigh = ~t(1 + 3Cvkt) = 1.327 ~t = L[1 + 3(0.109)]
If ~¢ = I and K~ --2.6
kf -- 1 + (1)(2.6 - 1) =
Kf~,ig h = 1 + [1.2499(1)][1.327(2.6)- 1) = 4.0625
Now
4.0556 ~f = X~i,~ - ~’f
The 4.0556 is from Fig. 2.4 and Table 2.2 where P(qhighgthigh) acts as 4.0556
standard deviations.
4.0625 - 2.6
~f - 4.0556 = 0.3606
The
Cv
~f
0.3606
-- × 100 = 4-13.87%
KU 2.6
Should the sort be taken as a one sided distribution Fig. 2.17
Fig. 2.17 one sided distribution Kf
q~,igh = ?/(1 + 2.5758Cvq) = 1.2146
K~hig~ = ~£t(1 + 2.5758Cvkt) = 1.2808
Substituting
K~igh = 1 ÷ [1.2146(1)][1.2808(2.6) - 1] = 3.8301
Table 2.7 Cv for q average values
Chapter 2
Q and T steel
Normal steel
Ave. aluminum
Cv
4- 8.33%
4- 5.26%
4- 7.33%
In the equation
Kf = 1 + q(K, - 1)
For qhigh
qhigh = ?/(1 -k 3Cvq) = 1.2499 ?/---- ?/[+3(0.0833)]
Kthigh = ~t(1 + 3Cvkt) = 1.327 ~t = L[1 + 3(0.109)]
If ~¢ = I and K~ --2.6
kf -- 1 + (1)(2.6 - 1) =
Kf~,ig h = 1 + [1.2499(1)][1.327(2.6)- 1) = 4.0625
Now
4.0556 ~f = X~i,~ - ~’f
The 4.0556 is from Fig. 2.4 and Table 2.2 where P(qhighgthigh) acts as 4.0556
standard deviations.
4.0625 - 2.6
~f - 4.0556 = 0.3606
The
Cv
~f
0.3606
-- × 100 = 4-13.87%
KU 2.6
Should the sort be taken as a one sided distribution Fig. 2.17
Fig. 2.17 one sided distribution Kf
q~,igh = ?/(1 + 2.5758Cvq) = 1.2146
K~hig~ = ~£t(1 + 2.5758Cvkt) = 1.2808
Substituting
K~igh = 1 ÷ [1.2146(1)][1.2808(2.6) - 1] = 3.8301