Application of Probability to Mechanical Design
53
40
2O
=N 10
x
11
2
3 4 5 7 10
20 30
50 70 i00
n Terms
Figure 2.4 One sided standard deviation, 2 and ~ for n cards selection for a
function of n variables for Pf = (9~)".
with the same conditions for a single card
Xmax = 2’576(+~)#x
Xmax = 1.01 #x
the same expression holds for Ymax and a second card
Zmax = 1.01 #x + 1.01 py
then
~z
when Fig. 2.4 and Table 2.2 are examined for n cards (and in this case n = 2),
53
40
2O
=N 10
x
11
2
3 4 5 7 10
20 30
50 70 i00
n Terms
Figure 2.4 One sided standard deviation, 2 and ~ for n cards selection for a
function of n variables for Pf = (9~)".
with the same conditions for a single card
Xmax = 2’576(+~)#x
Xmax = 1.01 #x
the same expression holds for Ymax and a second card
Zmax = 1.01 #x + 1.01 py
then
~z
when Fig. 2.4 and Table 2.2 are examined for n cards (and in this case n = 2),
