Reliability
211
Note the poor reliability with KF = 10 now change 28 from 27.4 x 10
-6
to 2.9 x 10 .6 on the pump and the shut off value 26 from 10.2 x 10 .6 to
1.98 x 10 .6 will change R1,2.
Calculate RI,2, again
R1,2 = 1 +~-(8760) exp[
(8760) = 0.8778
much better but still not great. Use 68.6 x 10 .6 for 21,2
B. Evaluate electric power with standby
R3 = [1 + 21@ (8760)] exp [- 21@ (8760)1 = 0.9806
Pressure flow regulators for a parallel setup (Eq. (4.33))
R4 = 2expl-1~6(8760) ] -exp[-2 1~6 (8760) 1 =0.8580
Need low extreme for less failures, and increased reliability.
Lets evaluate for top loop and then top and bottom loops in
parallel
Top Loop Rsystem = {0.8778}{0.9806}{0.8580} = 0.7385
Parallel Rsystem = 1 - (1 - 0.7385)(1 - 0.7385)
= 1 - 0.06838 = 0.9316
Need low extremes in all components, hence, increased reliability.
Motor pump set 1
R1,2= exp [-61~ (8760)]
R1,2 = 0.5483
This is not good! However, with standby yields 0.8778.
Redo B For electric
power with low extreme 2=(0.04x 10-6) x 10=
0.4 x 10-6/hr using Eq. (4.38)
R3 = 1 +-f-0-g(8760) exp -i-6g(8760) = (1.0035)(0.9965)