190
STATISTICAL RESPONSES FOR LINEAR STRUCTURES
Arbitrarily choose ( — 0.1. Using the constants in équation (7.101), Mathematica®
(1999) gave the following resuit: crv = 0.135 ft. Note that this resuit is about
one-fourth the value calculated by a different theory in Example Problern 7.3. A
doser agreement between the two results can be obtained by choosing Ç ~ 0.2,
for which
= 0.196 ft. A least squares fit of the constants â, £, w based on
équation (7.102) may lead to even doser agreement between the results for obtained in the two statistical methods. This exercise is left to the reader.
PROBLEMS
7.1 If y(t) is Gaussian with zéro mean and has a variance of by numerical intégration the probability that y(t) is outside the levels y — ± and y = ±2av. Check your results using Gaussian probability tables such as
found in a statistics reference book.
7.2 Suppose that y(t) is Gaussian, exists only over a narrow band of frequencies, and is a smooth function of time. Also assume that each cycle crosses
the mean level j/(t) = 0 so that the maxima always occur for y(t') >0 and the
minima always occur for y(t) < 0.
(a) Sketch a function y(t) which behaves as defined.
(b) The probability distribution for the peaks of y(t) so defined is given by
équation (7.7), the well-known Rayleigh distribution. Sketch p(a) as a function
of the amplitude a of y(t). Prove that the maximum value of p(a) occurs when
the amplitude is equal to the standard déviation, or a = (c) Compute the probability that any peak of y(t) exceeds these two values:
2 f00
/
a2 \
A *>'i“='»p(-^)
7.3 A digital time history of ÿ(t) is available in the form of points J/(tn)
even incréments of time, n = 1,2,... , n. Outline a computer-aided method that
will generate a probability density function p(y) from these data. How would
you check p(y) to see if it was Gaussian?
7.4 A schematic diagram of an instrument called a spectrum analyzer
is shown in Figure 7.7. The wave height input r?(t) is assumed to be a stationary ergodic random process. This input is filtered by a filter whose harmonie response function H(w) is a constant Ho in the narrow frequency band
(ixzo — Au>/2) < lu < (uiq +
The filter output y(t) is squared, and its time
average z(t) is calculated from
_
1
/*to/2
z(t) = E[y2(t)] =
y2{t)dt
T0 J-t0/2
The mean level of z(t), estimated from the output meter for sufficiently long
time penods tq, is
Précédent

- 206/342

Suivant