(c) The percentage of the wave height above the SWL may be determined
from Figure 2-13. Entering the figure with L2H/dJ = 190, the
value of (y„ - d)/H is found to be 0.833 or 83.3 percent.
Therefore,
yc = 0.833 H + d.
yc = 0.833(2.5) + 10 = 2.083 + 10 = 12.083 feet .
Also from Figure 2-13,
(y< “
---------- + 1 = 0.833 ,
H
thus
yf = (0.833- 1) (2.5) + 10 = 9.583 ft.
(d) The dimensionless wave profile is given on Figure 2-9 and is
approximately the one drawn for k2 = 1 - 10 . The results
obtained in (c) above can also be checked by using Figure 2-9.
For the wave profile obtained with k2 = 1 - 10-4, it is seen that
the SWL is approximately 0.17 H above the wave trough or 0.83 H
below the wave crest.
The results for the wave celerity determined under (b) above
can now be checked with the aid of Figure 2-15. Calculate
H
2.5
yf
9.583
= 0.261 .
Entering Figure 2-15 with
and
d3
190 ,
H
- = 0.261 ,
ït
it is found that
Ifterefore
c = 1083 ^(32.2) (9.583)' = 19 ft/sec .
2-58