7.11 (a)
(b)
(c)
7.12 (a)
(b)
(c) Since the reactions are irreversible, the concentrations of A and
B are zero and that of C is 0.3 M.
7.13
= 17.62 kJ mol
−1
7.14
= 107.8 kJ mol
−1
7.15
= −
−
⎛
⎝
−
.
5
0 008314
1
277
1
295
1
kJ mol
kJ/(Kmol)
K
K
⎜ ⎜ ⎜
⎞
⎠
⎟ ⎟ →
=
−
k 2
1
878 s
ln
ln
ln
k
k
E
R T
T
k
A
2
1
2
1
2
1
1
−
= −
−
⎛
⎝
⎜ ⎜
⎞
⎠
⎟ ⎟ →
−
− .
6 91
E
R k
k
T
T
A
(ln
ln )
/
/
.
= −
−
−
=
2
1
2
1
1
1
0 008314 kJ J/(Kmol)
K
K
(
.
. )
( /
) ( /
−
+
−
10 41 11 87
1 293
1 303 ) )
ln
ln
k
k
E
R T
T
E
A
A
2
1
2
1
1
1
−
= −
−
⎛
⎝
⎜ ⎜
⎞
⎠
⎟ ⎟ →
= − −
−
−
R k
k
T
T
(ln
ln )
/
/
2
1
2
1
1
1
E
R k
k
T
T
A
(ln
ln )
/
/
.
= −
−
−
=
2
1
2
1
1
1
0 008314 kJ/( (Kmol)
K
K
(ln
ln )
( /
) ( /
)
20
10
1 330
1 298
−
−
ln
ln
k
k
E
R T
T
E
A
A
2
1
2
1
1
1
−
= −
−
⎛
⎝
⎜ ⎜
⎞
⎠
⎟ ⎟ →
= − −
−
−
R k
k
T
T
(ln
ln )
/
/
2
1
2
1
1
1
d C
d
B
s
M
M s
[ ]
[ ] ( .
)( .
)
.
t
k f
= −
=
=
−
−
2
1
1
0 1
0 1
0 1
d B
d
A
B
s
M
[ ]
[ ]
[ ]
( .
)( .
)
t
k
k
f
f
= +
−
= +
−
1
2
1
0 1
0 1
( .
)( .
)
−
=
−
0 1
0 1
0
1
s
M
d A
d
A
s
M
M s
[ ]
[ ]
( .
)( .
)
.
t
k f
= −
= −
= −
−
1
1
0 1
0 1
0 1
− −1
d A
d
A
d B
d
A
B
d
[ ]
[ ]
[ ]
[ ]
[ ]
[
t
k
t
k
k
f
f
f
= −
= +
−
1
1
2
C C
d
B
]
[ ]
t
k f
= − 2
[ ]
[ ]
[ ] [ ]
.
A
B
s
s
so A
B
M
=
=
=
=
−
−
1
1
1
0 1
1
1
d B
d
s
M
s
M
[ ]
(
)( .
) (
)( .
)
t
= +
−
=
−
−
1
01
1
01
0
1
1
d A
d
s
M
s
M
[ ]
(
)( .
) (
)( .
)
t
= −
+
=
−
−
1
01
1
01
0
1
1
d A
d
A
B
d B
d
A
[ ]
[ ]
[ ]
[ ]
[ ]
t
k
k
t
k
k
f
b
f
b
= −
+
= +
− [ [ ]
B
ANSWERS TO PROBLEMS
451
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