4.1 Newton Model
89
a)
t
(tmax = 100 × 0.1 max,min = ± 5.0)
b)
t
σ
(tmax = 100 × 0.1 σmax,min = ± 10.0)
c)
t
v
(tmax = 100 × 0.1 p,max,min = ± 5.0)
d)
σ
( max,min = ± 5.0 σmax,min = ± 10.0)
e)
σ
( max,min = ± 5.0 σmax,min = ± 10.0)
f)
σ
( max,min = ± 5.0 σmax,min = ± 10.0)
Fig. 4.7 Response analysis of the specific Newton model with material data: η = 1.0. Prescribed
Sine strain history with data: a = 5.0, a–d T = 4.0; = 0.1, N = 100, e T = 40.0; = 1.0,
N = 100, f T = 400.0; = 10.0, N = 100