576
10 Particle Physics – II
Fig. 10.9
Actually the value of R will be slightly greater than 2 because of an
increased value of α s , the running coupling constant.
10.58 E = ψ |H | ψ
ψ | ψ =
∞
0
e
−r/a
−
2
2μ
d
2
dr 2 +
2
r
d
dr
+ Br
e
−r/a
.4πr
2 dr
∞
0
e −2r/a .4πr 2 dr
where μ = m q
2 is the reduced mass
E =
2
2μ
1
a 2 +
3
2
Ba
(1)
Précédent

- 593/651

Suivant