Answers to Problems of the A Groups
441
CHAPTER 11
1. 22.0 ml
13. 498 ml
2. 619 cm
14. 0.279 g
3. 725.6 torr
15. 832 ml
4. 13.9 lb/in
2
16. 134 g/ml
5. 240 ml
17. 2.73 g/ml
6. 841 ml
18. (a) 1.96 g/liter
7. 475 torr
(b) L73
8. 107 torr
19
'
68
'
9. 3.3 atm
2
°'
2?? m '
.. , _,
,-, n
,
,
21. 34.2 g/mole
10. 3.53 x 10
10 molecules
,. ,„, ,
22. 0.350 atm
11. 203 ml
12. (a) 402 ml
(b) 389 ml
23. (a) 0.075 atm N 2 , 0.250 atm N 2 O, 0.175 atm CO 2
(b) resultant pressure is 0.325 atm
partial pressures are 0.075 atm N 2 and 0.250 atm N 2 O
24. 9.54 g/mole
32. 22.1% H 2 and 77.9% O 2
25. 87.8 g/mole
33. 30.6 kg
26. C 4 H 8 O 2
34. (a) 7.94 x 10
3 liters/day
27. 36.8 Ibs/in*
(b) 10 '
2 kg/day
28. 48.8 sec
35 ' <*>
(b) 618 g/day
29 ' ''
66 ml/mln
36. C 2 H 4 NO
30. 11.6 g
31. (a) Balloon would rise
(b) It would lift 2.9 g
CHAPTER 12
1. The answers to these problems are given as the numerical coefficients needed to
balance the equations, and in the order in which the substances appear in the
unbalanced equations.
(a) 2, 2, 1
(c) 2, 2, 2, 1
(e) 1, 3, 2, 3
(b) 2, 2, 4, 1
(d) 3, 4, 1, 4
(f) 1, 4, 3, 4