67
Chapter 8: Applications of Derivatives
Using the Closed Interval
Method
451– 455 Find the absolute maximum and absolute
minimum of the given function using the closed
interval method.
451. f
(x) = 3x
2
– 12x + 5 on [0, 3]
452. f
(x) = x
4
– 2x
2
+ 4 on [–2, 3]
453. f x
x
x
( ) =
+
2
1
on [0, 3]
454. f t t
t
( ) =
−
4
2 on [–1, 2]
455. f
(x) = x – 2 cos x on [–π, π]
448.
449.
450.
Point A corresponds to which of the
following?
I. local maximum
II. local minimum
III. absolute maximum
IV. absolute minimum
Chapter 8: Applications of Derivatives
Using the Closed Interval
Method
451– 455 Find the absolute maximum and absolute
minimum of the given function using the closed
interval method.
451. f
(x) = 3x
2
– 12x + 5 on [0, 3]
452. f
(x) = x
4
– 2x
2
+ 4 on [–2, 3]
453. f x
x
x
( ) =
+
2
1
on [0, 3]
454. f t t
t
( ) =
−
4
2 on [–1, 2]
455. f
(x) = x – 2 cos x on [–π, π]
448.
449.
450.
Point A corresponds to which of the
following?
I. local maximum
II. local minimum
III. absolute maximum
IV. absolute minimum