12.11 Summary
505
Answers to Selected Problems
12.1 First using Eq. (3.3) change 0.55 dB/km to 0.127 km
−1 and 0.28 dB/km to
0.0645 km
−1 . Then from Eq. (12.1) L eff (1310) = 7.9 km and L eff (1550) =
14.9 km.
12.2 Using Eq. (3.3) change 0.20 dB/km to 0.046 km
−1 and 0.40 dB/km to
0.092 km
−1 . Then using Eq. (12.1) it follows that L eff (1550) = 18.3 km
and L eff (1310) = 10.6 km. Then using Eq. (12.5), P th (1550) = 12.4 mW and
P th (1310) = 21.4 mW.
12.3 The following nine 3rd-order waves are generated due to FWM:
ν113 = 2(ν2 - ν) – (ν2 + ν) = ν2 - 3ν.
ν112 = 2(ν2 - ν) – ν2 = ν2 - 2ν.
ν123 = (ν2 - ν) + ν2 – (ν2 + ν) = ν2 - 2ν.
ν223 = 2ν2 – (ν2 + ν) = ν2 - ν = ν1.
ν132 = (ν2 - ν) + (ν2 + ν) – ν2 = ν2.
ν221 = 2ν2 – (ν2 - ν) = ν2 + ν = ν3.
ν231 = ν2 + (ν2 + ν) – (ν2 - ν) = ν2 + 2ν.
ν331 = 2(ν2 + ν) – (ν2 - ν) = ν2 + 3ν.
ν332 = 2(ν2 + ν) – ν2 = ν2 + 2ν.
12.4 P peak = 11.0 mW; L disp = 43 km, L period = 67.5 km; P peak = 3.1 mW.
12.6 (a) From the equation L coll = 80 km;
(b) From the given condition L amp = 0.5 L coll ≤ 40 km.
12.7 From the equation and conditions in Problem 12.6, λ max =
T s
DL amp
= 2 nm.
Therefore, the maximum number of channels = 2.0 nm/0.4 nm = 5.
References
1. A.D. Ellis, M.E. McCarthy, M.A.Z. Khateeb, I.M. Sorokina, N.J. Doran, Performance limits
in optical communications due to fiber nonlinearity: Tutorial. Adv. Optics Photonics 9(3),
429–502 (2017)
2. J. Toulouse, Optical nonlinearities in fibers: Review, recent examples, and systems applications.
J. Lightw. Technol. 23, 3625–3641 (2005)
3. R.H. Stolen, The early years of fiber nonlinear optics. J. Lightw. Technol. 26(9), 1021–1031
(2008)
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