Direct Current and Transient Analysis
145
3. W
W
1
f
2
f
ft lb
ft lb
ϭ
ϭ
ϭ
ϭ
50 0 737 36 85
16 0 737 11 79
* .
.
* .
.
⋅
⋅
4. W
W
1
2
kW h
kW
ϭ
ϭ
ϭ
ϭ
50 3 6 10
0 0000138
16 3 6 10
0 00000444
6
6
/ . *
.
/ . *
.
Ϫ
Ϫ
h h
MATLAB Solution
>> R1=3; R2=2; C1=1; C2=2; VC=10;
>> VC1=VC; VC2=(R2/(R1+R2))*VC;
>> W1 _ J=0.5*C1*VC1^2,W2 _ J=0.5*C2*VC2^2
W1 _ J =
50
W2 _ J =
16
FIGURE 2.41
Electrical network of Example 2.5.
R 3 = 4 Ω
R 1 = 3 Ω
R 2 = 2 Ω
C 1 = 1 F
C 2 = 2 F
V = 10 V
FIGURE 2.42
Equivalent DC circuit of Figure 2.41.
V C 1 = 10 V
V C 2 =V R 2
R 1 = 3 Ω
R 2 = 2 Ω
C 1 = 1 F
V = 10 V
CRC_47760_CH002.indd 145
CRC_47760_CH002.indd 145
7/23/2008 1:38:46 PM
7/23/2008 1:38:46 PM