338 ~ Theory ofComputer Science
Thus we have shown that the three initial primitive recursive functions are
Turing-computable. Next we construct Turing machines that can perform
composition, recursion. and minimization.
11 .4.7 CONSTRUCTION OF THE TURING MACHINE THAT
CAN PERFORM COMPOSITION
Let fIC-'l' X.2' ..., .\,,)•...• fiJxI, .... XIII) be Turing-computable functions. Let
g(YI' .. " YI.) be Turing-computable. Let h("I, ... , XIII) = g(fl(XI ...• x m ) .•••
.MXi' . , ., XIII»' We construct a Turing machine that can compute h(aj, ...• am)
for given arguments aj, .... am' This involves the following steps:
Step 1 Construct Turing machines All' .... M k which can compute fl' ... , .I;.
respectively. For the TMs Mj, .... lvII.:' let T' = {I, b, Xl. X.:; • .... x n , y} and
X = 1°1,]
1
0m X in by. But the number of states for these TMs will vary.
Let 111 + 1.
11k + 1 be the number of states for /\.1 1 , .... A'h. respectively.
As usuaL the initial state is (jo and the states for M i are qQ, ... , q,,;, As in the
earlier constructions. the set Pi of quadruples for M i is constructed in such a
way that there is no quadruple starting with ql1;'
Step 2 Let f;(ai' ..., am) = b i for i = 1. 2, ..., k. At the end of step 1,
we have M;'s and the computed values bi's. As g is Turing-computable. we
can construct a TM A'h+l which can compute g(b] • .... b k )· For M k + l •
X , - I hl .'
1 0m ' l .
-
X \ •••
X III 7)
(\Ve use different markers for M k + 1 so that the TM computing h to be
constructed need not scan the inputs a] . ... , am') Let I1k+\ + 1 be the number
of states of M k +]. As in the earlier constructions, M k + 1 has no quadruples
starting with qk+ I'
Step 3 At the end of step 2. we have TMs M I , ... , M b lvh+1 which give
b l . . . . . bin and g(b] . .... bJ = c (say). respectively. So we are able to
compute h(al' .... am) using k + 1 Turing machines. Our objective is to
construct a single TM kh+.2 which can compute heal' ..., an,). We outline the
construction of M without giving the complete details of the encoding
mechanism. For M. let
T' = {1. b, Xi' " .. X"I' x'\.
(1) In the beginning, lv! simulates Mj • As a result. the value b j =
fi(al' ... , am) is obtained as output. Thus we get the tape expression
1°\x I 1!!2x. :; ... 1(1mx m l bl y which is the same as that obtained by M 1
while halting. lv! does not halt but cbanges y to x'] and adds by to the
right of X'I' The head moves to the left to reach the beginning of X.
Précédent

- 351/434

Suivant