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Black holes in string theory
that is needed to complete the resemblance to (lO.lOI) is a further warping
approximating H- I in the xO-direction. In any case, in its present form,
the metric does not have a finite horizon 'area', because gll vanishes at the
horizon: it requires a further warping approximating H. In fact, the missing
ingredient is supplied by adding momentum in the x I-direction. Since the ex treme
solution is boost invariant, we cannot add momentum simply by boosting it.
The generalization arises [21] because the solutions have a null-bypersurface
orthogonal isometry which permits the replacement
(dx~2 _ (dx l )2 -+ (dx 0 )2 _ (dx l )2 + Hp(r)(dx 0 _ dx l )2
(l0.144)
for an arbitrary harmonic function Hp(r). This is exactly what happens if we
do a Kaluza-Klein reduction along the x I-direction but with a non-zero offdiagonal component in the metric gOl/gll = Hp(r)-I (see exercise 7). Indeed,
the resulting metric can be obtained from a non-extreme metric by this means:
the dilaton and gauge potential form fields are unaffected. The final form of the
metric is
ds 2 = HS-I/4ii~3/4[(dxO)2 _ (dx l )2 + Hp(dx 0 - dx l )2]
_ HS-I/4iill/4[(dx 2 )2 + ... + (dx S )2] _ H:'4iill/4[dr 2 + r2dn~].
(10.145)
We may write the hannonic functions in the form
2
_ r.
L2
r2
H. = 1 +'2
H5 = I +-f Hp=..J:..
(10.146)
r
r
r2
where, using (10.106), (10.131) and (10.140),
2
2 I (27r #)4 cl
rf = q. g,a' (27r #)4 L~ = qsg,a' rp = ng,a V. "2
V4
4
R
(10.147)
with R the radius of the circle upon which the x l-coordinate is compactified, and
n an integer specifying the (right-moving) momentum P = n/ R on the circle.
Adding this momentum breaks a further half of the supersymmetries leaving a
total of four preserved supersymmetry charges. This corresponds to.N = I
supersymmetry in five dimensions. The 'area' A H of the event horizon is defined
as the (eight-dimensional) volume of the time slice at the horizon. Taking the
limit r -+ 0 from above, this gives a product of factors, one from each of the
three disjoint pieces of the metric:
AH = [(r~3/4L;I/4rp )27r R][(r:/ 4 L;1/4)4V4)[(r:/ 4 L~/4)327r2]
= 47r 3 RV4r.Lsrp.
(10.148)
The surface gravity and, hence, the black-hole temperature is zero, as might be
expected from an extreme black hole (see exercise 7). Using the (generalized)
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