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3. Relativistic Quantum Mechanics
Since energy and momentum are merely different components of a 4-vector,
an attempt to base a relativistic theory on the relation
2
2 )
1/2
E = +(p + m
(3.6)
is unattractive, as well as having obvious difficulties in interpretation for the
square root operator. Schr¨ odinger, before settling for the less ambitious nonrelativistic Schr¨ odinger equation, and later Klein and Gordon, attempted to
build relativistic quantum mechanics (RQM) from the squared relation
2
2
E
2 = p + m .
(3.7)
Using the operator replacements for E and p we are led to
−∂
2 φ/∂t
2 = (−∇
2 + m
2 )φ
(3.8)
which is the Klein–Gordon equation (KG equation). We consider the case of a
one-component scalar wavefunction φ(x, t): one expects this to be appropriate
for the description of spin-0 bosons.
3.1.1 Solutions in coordinate space
In terms of the D’Alembertian operator
∂
2
❗ ≡ ∂ μ ∂
μ =
− ∇
2
(3.9)
∂t 2
the KG equation reads:
(❗ + m
2 )φ(x, t) = 0.
(3.10)
Let us look for a plane-wave solution of the form
−iEt+ip·x
−ip·x
φ(x, t) = N e
= N e
(3.11)
where we have written the exponent in suggestive 4-vector scalar product
notation
μ
p · x = p μ x = Et − p · x
(3.12)
and N is a normalization factor which need not be decided upon here (see section 8.1.1). In order that this wavefunction be a solution of the KG equation,
we find by direct substitution that E must be related to p by the condition
2
2
E
2 = p + m .
(3.13)
This looks harmless enough, but it actually implies that for a given 3-momentum
p there are in fact two possible solutions for the energy, namely
2
2 )
1/2
E = ±(p + m
.
(3.14)
As Schr¨ odinger and others quickly found, it is not possible to ignore the negative solutions without obtaining inconsistencies. What then do these negativeenergy solutions mean?
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