416
K. Example of a Cross Section Calculation
and, after some routine juggling, arrive at the result
dq
2 = 2k
′ 2 d(cos θ).
(K.46)
If we introduce the variable ν defined, for elastic scattering, by
2p · q ≡ 2M ν = −q
2
(K.47)
we have immediately
dν =
k
′ 2
M
d(cos θ).
Similarly, if we introduce the variable y defined by
(K.48)
y = ν/k
(K.49)
we find
for elastic scattering.
dy =
k
′ 2
2πkM
dΩ
(K.50)
K. Example of a Cross Section Calculation
and, after some routine juggling, arrive at the result
dq
2 = 2k
′ 2 d(cos θ).
(K.46)
If we introduce the variable ν defined, for elastic scattering, by
2p · q ≡ 2M ν = −q
2
(K.47)
we have immediately
dν =
k
′ 2
M
d(cos θ).
Similarly, if we introduce the variable y defined by
(K.48)
y = ν/k
(K.49)
we find
for elastic scattering.
dy =
k
′ 2
2πkM
dΩ
(K.50)