104
Chapter 2
o
lbo
20o
~m ksi
Figure 2.38 Bull gear material and stress due to loading.
solving for d
3
d3_ 46,582 16 _ 17.670 in
3
13,426
d = 2.605" ~b [does not include sudden loading]
b. Section C.4 asas - 3~s curve with f.s. = 3 and with a’ r = 10,000 psi
d3 _ 46,582 16 23.724 in
3
(2.112)
10,000 n
d = 2.8734"~b [does not include sudden loading]
c. Section C.5
Now obtain a solution for d using the coupling equation Eq. (2.42),
a Monte Carlo program could be used here. Here z=-6 standard
deviations, Py=9.8659 × 10 -~° from Section C.5 with the a’ r Eq. (2.108)
simplified by dropping d.
, [-[ 32Mm’~ 2 [ 16Tr\2"]
1/ 2
and
, 16Tin x/~
a m -- ~zd3
Chapter 2
o
lbo
20o
~m ksi
Figure 2.38 Bull gear material and stress due to loading.
solving for d
3
d3_ 46,582 16 _ 17.670 in
3
13,426
d = 2.605" ~b [does not include sudden loading]
b. Section C.4 asas - 3~s curve with f.s. = 3 and with a’ r = 10,000 psi
d3 _ 46,582 16 23.724 in
3
(2.112)
10,000 n
d = 2.8734"~b [does not include sudden loading]
c. Section C.5
Now obtain a solution for d using the coupling equation Eq. (2.42),
a Monte Carlo program could be used here. Here z=-6 standard
deviations, Py=9.8659 × 10 -~° from Section C.5 with the a’ r Eq. (2.108)
simplified by dropping d.
, [-[ 32Mm’~ 2 [ 16Tr\2"]
1/ 2
and
, 16Tin x/~
a m -- ~zd3