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Coastal Engineering: Theory and Practice
Passive pressure = 16.27[(6.8 — 1.5) + (2/3 x 0.97)]
= 96.31
pW + Passive pressure
198.678 + 96 31
Check for sliding =----- t—-- -------------------------------- =---------- — r
------Active pressure
155.197
= 1.9 > 1.5. Hence Safe.
Problem X
Design the diaphragm wall for the critical case under three cases. Case 1:
highest high tide level, Case 2: Low tide level and Case 3: high tide level on
sea side and empty on land side. Consider the following parameters: grade
of concrète = M35, grade of Steel = Fe250, clear cover = 75 mm and the
dead loads, water: 10 kN/m3, RCC: 2.5 kN/m3, Steel: 7.85 kN/m3. Consider
y dry = 18 kN/m3, 7sat = 20 kN/m3, 7W = 10.25 kN/m3, 7' = 9.75 kN/m3
and $ = 32°.
Case 1: In case of highest high tide level